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Indian Navy AA (Artificer Apprentice) Physics — practice by topic

Browse 226 questions across 57 Physics topics. Choose what you want to revise, then open a question to check its answer and worked solution.

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Work done by a constant force $\vec{F}$ when the body moves through displacement $\vec{s}$ is:

  1. $W = F + s$
  2. $W = F s \cos\theta$
  3. $W = F s \sin\theta$
  4. $W = F / s$
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Correct answer: B. $W = F s \cos\theta$

Work is defined as $W = \vec{F} \cdot \vec{s} = F s \cos\theta$, where $\theta$ is the angle between $\vec{F}$ and $\vec{s}$. Work is maximum ($Fs$) when force and displacement are parallel and zero when they are perpendicular ($\cos 90° = 0$). Negative work happens when force opposes motion (e.g. friction).

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For a body on a horizontal surface, the NORMAL FORCE N equals:

  1. mg/2
  2. mg (weight)
  3. 2mg
  4. Zero
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Correct answer: B. mg (weight)

For a body at rest on a horizontal surface, N must balance gravity: N = mg. (If inclined, N = mg cos θ; if accelerating vertically, N changes accordingly.)

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A 5 kg block is pushed with 30 N along a frictionless surface. Acceleration:

  1. 0.17 m/s²
  2. 2 m/s²
  3. 6 m/s²
  4. 150 m/s²
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Correct answer: C. 6 m/s²

We have a = F/m. That is a = 30/5. So a = 6 m/s². On frictionless surface, all applied force goes into acceleration.

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