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Indian Navy AA (Artificer Apprentice) Wave Optics — practice questions

Explore 7 free Wave Optics questions in Indian Navy AA (Artificer Apprentice) Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Wave Optics questions and exercises with answers

Showing questions 1–7 of 7.

Two waves with the same frequency and constant phase difference are called:Read the answer and worked solution →For maximum brightness in Newton's rings (reflected light, air film), what is the radius of n-th bright ring? (R = lens radius, λ = wavelength)Read the answer and worked solution →Two coherent sources have intensities I1 = 9I and I2 = I. Maximum and minimum intensities in interference pattern:Read the answer and worked solution →In Young's experiment, intensity at a point where path difference is λ/4:Read the answer and worked solution →Intensity at point in YDSE with phase difference φ between two waves of equal amplitude:Read the answer and worked solution →Reflection or refraction?Read the answer and worked solution →True or false: opticsRead the answer and worked solution →

Worked practice questions

Two waves with the same frequency and constant phase difference are called:

  1. Incoherent
  2. Coherent
  3. Polarized
  4. Diffracted
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Correct answer: B. Coherent

Coherent waves maintain a constant phase relationship, required for stable interference patterns. Laser light is coherent. Sunlight is incoherent.

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For maximum brightness in Newton's rings (reflected light, air film), what is the radius of n-th bright ring? (R = lens radius, λ = wavelength)

  1. sqrt(nλR)
  2. sqrt((2n+1)λR/2)
  3. sqrt(nλR/2)
  4. sqrt(nλ/R)
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Correct answer: B. sqrt((2n+1)λR/2)

In Newton's rings (reflected light), there is a phase change at the lower glass surface but not at the upper. **For bright ring:** 2t = (n + 1/2)λ where t = r²/(2R). **So r_n = sqrt((2n+1)λR/2).**

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Two coherent sources have intensities I1 = 9I and I2 = I. Maximum and minimum intensities in interference pattern:

  1. 10I, 8I
  2. 16I, 4I
  3. 9I, I
  4. 16I, 0
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Correct answer: B. 16I, 4I

Amplitudes A1 ∝ sqrt(9I) = 3 sqrt(I), A2 = sqrt(I). We have I_max = (A1 + A2)². So I_max = 16I. We have I_min = (A1 - A2)². So I_min = 4I. (Not 0 since intensities are unequal.)

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