Three capacitors of 2 µF each are connected in series. The equivalent capacitance is
- 2 µF
- 2/3 µF
- 6 µF
- 1/6 µF
Show answer and solution
Correct answer: B. 2/3 µF
1. In series, 1/Cₑ = 1/C + 1/C + 1/C = 3/C.
2. Cₑ = C/3 = 2/3 µF.
3. Option (A) is the parallel result, so the trap is for students who mix the rules.
_Source: syllabus Physics Part I, Ch 2 §2.14.1_