alleryStart learning →In an ISOCHORIC process, work done equals:
- Negative of heat
- Maximum
- Zero
- ΔU
Show answer and solution
Correct answer: C. Zero
Isochoric = constant volume.
Since dV = 0, work W = ∫P dV = 0. All heat absorbed becomes change in internal energy: Q = ΔU.
Indian Navy AA (Artificer Apprentice) Thermodynamics — practice questions
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In an ISOCHORIC process, work done equals:Read the answer and worked solution →In an isothermal expansion of ideal gas, the work done BY the gas is +500 J. The heat absorbed by the gas is:Read the answer and worked solution →Isothermal bulk modulus of an ideal gas equals:Read the answer and worked solution →For an adiabatic process of an ideal gas, TV^(γ-1) = constant. If T₁ = 300 K and V₂ = 2V₁ for γ = 5/3, then T₂:Read the answer and worked solution →n-type or p-type?Read the answer and worked solution →True or false: semiconductorsRead the answer and worked solution →
Worked practice questions
In an isothermal expansion of ideal gas, the work done BY the gas is +500 J. The heat absorbed by the gas is:
- +500 J
- 0
- Cannot determine
- -500 J
Show answer and solution
Correct answer: A. +500 J
Isothermal: ΔU = 0. So ΔU = Q - W
→ 0 = Q - 500 → Q = +500 J. All the work done comes from absorbed heat.
Isothermal bulk modulus of an ideal gas equals:
- P
- P/γ
- -V/P
- γP
Show answer and solution
Correct answer: A. P
Bulk modulus K = -V(dP/dV).
**For isothermal:** dP/dV = -P/V, so K_iso = -V × (-P/V) = P.
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