Start learning →

HPCET Dual Nature of Radiation and Matter — practice questions

Explore 41 free Dual Nature of Radiation and Matter questions in HPCET Physics. Open each question or exercise to read its content, reference answers and available explanation.

Practise Dual Nature of Radiation and Matter with Quill →

Dual Nature of Radiation and Matter questions and exercises with answers

Showing questions 1–30 of 41.

Photoelectric effect was explained by:Read the answer and worked solution →Photon energy:Read the answer and worked solution →de Broglie wavelength λ associated with a particle of momentum p:Read the answer and worked solution →In photoelectric effect, intensity of light affects:Read the answer and worked solution →Einstein's photoelectric equation:Read the answer and worked solution →Threshold frequency ν₀ for photoemission:Read the answer and worked solution →de Broglie wavelength of electron accelerated through V volts:Read the answer and worked solution →For very slow electron (low momentum), de Broglie wavelength is:Read the answer and worked solution →Davisson-Germer experiment demonstrated:Read the answer and worked solution →For photon, momentum p = E/c =Read the answer and worked solution →A metal has work function 2.0 eV. Light of wavelength 400 nm (3.1 eV) shines on it. Max KE of photoelectrons:Read the answer and worked solution →Threshold wavelength for a metal with work function 3 eV:Read the answer and worked solution →de Broglie wavelength of a 1 kg ball moving at 1 m/s:Read the answer and worked solution →For accelerated electron with KE = 100 eV, de Broglie wavelength:Read the answer and worked solution →Energy of photon with momentum 3.3 × 10⁻²⁵ kg m/s:Read the answer and worked solution →For photoelectric experiment, plot of KE_max vs frequency ν is:Read the answer and worked solution →In Compton scattering at 90° (cos 90 = 0), wavelength shift:Read the answer and worked solution →Maximum velocity of photoelectrons from a metal of work function 2 eV, illuminated by 200 nm light:Read the answer and worked solution →de Broglie wavelength of proton accelerated through 1000 V:Read the answer and worked solution →Photon flux (photons/sec) for 1 W of green light (λ = 550 nm):Read the answer and worked solution →Heisenberg uncertainty: for an electron in atom (Δx ~ 10⁻¹⁰ m), minimum momentum uncertainty:Read the answer and worked solution →NEET · Physics · Photoelectric — Spot the ErrorRead the answer and worked solution →Trace photoelectrons to their causeRead the answer and worked solution →Knock out the photoelectric mythsRead the answer and worked solution →Knock out the false photon claimsRead the answer and worked solution →Catch the false line on lightRead the answer and worked solution →Intensity or frequencyRead the answer and worked solution →Place the discoveriesRead the answer and worked solution →Who did whatRead the answer and worked solution →Type the quantum termRead the answer and worked solution →

Worked practice questions

Photoelectric effect was explained by:

  1. Galileo
  2. Einstein (1905, light as quanta of energy hν)
  3. Newton
  4. Faraday
Show answer and solution

Correct answer: B. Einstein (1905, light as quanta of energy hν)

Einstein won 1921 Nobel Prize for explaining photoelectric effect: light comes in discrete energy packets (photons) of energy hν. Classical wave theory could not explain observed features.

Open this question →

Photon energy:

  1. Planck constant alone
  2. hν (= hc/λ)
  3. kT
  4. mc²
Show answer and solution

Correct answer: B. hν (= hc/λ)

We have E = hν. So E = hc/λ. h = 6.626 × 10⁻³⁴ J s (Planck's constant). Higher frequency (shorter wavelength) = higher energy photons.

Open this question →

de Broglie wavelength λ associated with a particle of momentum p:

  1. hc/p
  2. h × p
  3. h / p (wave-particle duality)
  4. p / h
Show answer and solution

Correct answer: C. h / p (wave-particle duality)

λ = h/p. Every moving particle has wave-like properties with wavelength inversely proportional to momentum. For ordinary objects λ is unmeasurably small for electrons λ is on atomic scale.

Open this question →

How to practise

  1. Choose a Dual Nature of Radiation and Matter question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

More Physics topics