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A metal has work function 2.0 eV. Light of wavelength 400 nm (3.1 eV) shines on it. Max KE of photoelectrons:
A3.1 eV
B1.1 eV
C5.1 eV
D2.0 eV
Answer & Solution
Correct answer: B. 1.1 eV
KE_max = hν - φ = 3.1 - 2.0 = 1.1 eV. Stopping potential V₀ = 1.1 V.
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