alleryde Broglie wavelength of proton accelerated through 1000 V:
A100 Å
BEqual
CSame as electron at 1000 V
DSmaller by sqrt(m_p/m_e) ≈ 42.8 → about 0.0286 Å
Answer & Solution
Correct answer: D. Smaller by sqrt(m_p/m_e) ≈ 42.8 → about 0.0286 Å
λ = h/sqrt(2mqV).
Same V, more massive particle → shorter λ.
Ratio λ_p/λ_e = sqrt(m_e/m_p) ≈ 1/42.8. For electron at 1000 V: ~0.388 Å.
**So proton:** ~0.0091 Å.
(Heavier ions have even shorter de Broglie λ.)
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