alleryEnergy of photon with momentum 3.3 × 10⁻²⁵ kg m/s:
A100 eV
B1 J
CE = pc = 3.3 × 10⁻²⁵ × 3 × 10⁸ ≈ 10⁻¹⁶ J ≈ 620 eV
D6.6 × 10⁻³⁴ J
Answer & Solution
Correct answer: C. E = pc = 3.3 × 10⁻²⁵ × 3 × 10⁸ ≈ 10⁻¹⁶ J ≈ 620 eV
We have E = pc.
That is E = (3.3 × 10⁻²⁵)(3 × 10⁸).
So E = 9.9 × 10⁻¹⁷ J ≈ 620 eV.
(X-ray energy.) Corresponding λ = h/p = 6.6 × 10⁻³⁴ / 3.3 × 10⁻²⁵ = 2 × 10⁻⁹ m = 2 nm (X-ray range).
Keep practising Dual Nature of Radiation and Matter
Browse all Dual Nature of Radiation and Matter questions for JEE Advanced, or explore more Physics topics.