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HomeJEE MainPhysicsDual Nature of Radiation and Matter › Energy of photon with momentum 3.3 × 10⁻²⁵ kg m/s:

Energy of photon with momentum 3.3 × 10⁻²⁵ kg m/s:

A100 eV
B1 J
CE = pc = 3.3 × 10⁻²⁵ × 3 × 10⁸ ≈ 10⁻¹⁶ J ≈ 620 eV
D6.6 × 10⁻³⁴ J
Answer & Solution
Correct answer: C. E = pc = 3.3 × 10⁻²⁵ × 3 × 10⁸ ≈ 10⁻¹⁶ J ≈ 620 eV
E = pc = (3.3 × 10⁻²⁵)(3 × 10⁸) = 9.9 × 10⁻¹⁷ J ≈ 620 eV. (X-ray energy.) Corresponding λ = h/p = 6.6 × 10⁻³⁴ / 3.3 × 10⁻²⁵ = 2 × 10⁻⁹ m = 2 nm (X-ray range).
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