alleryde Broglie wavelength of electron accelerated through V volts:
Ah / V
Bh / sqrt(2 m e V) ≈ 12.27/sqrt(V) Å
CmV
Dh × V
Answer & Solution
Correct answer: B. h / sqrt(2 m e V) ≈ 12.27/sqrt(V) Å
KE = eV, p = sqrt(2 m × KE) = sqrt(2 m e V). λ = h/p.
**For electron:** λ ≈ 12.27/sqrt(V) Å (V in volts).
e.g., V = 100 V: λ ≈ 1.23 Å.
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