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Photon energy:

APlanck constant alone
Bhν (= hc/λ)
CkT
Dmc²
Answer & Solution
Correct answer: B. hν (= hc/λ)
We have E = hν. So E = hc/λ. h = 6.626 × 10⁻³⁴ J s (Planck's constant). Higher frequency (shorter wavelength) = higher energy photons.
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