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CBSE Class 10 Mensuration: Surface Areas & Volumes — practice questions

Explore 104 free Mensuration: Surface Areas & Volumes questions in CBSE Class 10 Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Mensuration: Surface Areas & Volumes questions and exercises with answers

Showing questions 1–30 of 104.

Area of a circle of radius r is:Read the answer and worked solution →Area of a sector subtending angle θ (deg) at the centre of a circle of radius r is:Read the answer and worked solution →Volume of a cone with radius r and height h is:Read the answer and worked solution →Volume of a sphere of radius r equals:Read the answer and worked solution →Match each solid to its total surface-area formula.Read the answer and worked solution →CLASS10 · Mathematics · Areas Related to CirclesRead the answer and worked solution →CLASS10 · Mathematics · Surface Area & VolumeRead the answer and worked solution →The formula for the area of a sector of a circle of radius r and angle theta (in degrees) isRead the answer and worked solution →The formula for the length of an arc of a circle of radius r and angle theta (in degrees) isRead the answer and worked solution →A sector with central angle 90 degrees in a circle of radius 14 cm has areaRead the answer and worked solution →A circle has radius 7 cm. The area of a semicircle isRead the answer and worked solution →A segment of a circle is the region bounded by a chord and the correspondingRead the answer and worked solution →The area of a quadrant of a circle of radius r isRead the answer and worked solution →The area of a sector of a circle of radius 14 cm with central angle 60 degrees isRead the answer and worked solution →The length of the minute hand of a clock is 14 cm. The area swept by the minute hand in 5 minutes isRead the answer and worked solution →The arc length of a sector with radius 21 cm and angle 60 degrees isRead the answer and worked solution →A circular park of radius 20 m is to be enclosed by fencing. The length of fencing needed isRead the answer and worked solution →The area of a sector subtending 45 degrees at the centre of a circle of radius 8 cm isRead the answer and worked solution →A horse is tethered to a corner of a square field of side 15 m by a 7 m rope. The area the horse can graze isRead the answer and worked solution →A circular pizza of radius 14 cm is cut into 6 equal sectors. The area of each sector isRead the answer and worked solution →A wire is bent in the form of a circle of radius 28 cm. The same wire is then re-bent in the form of a square. The side of the square isRead the answer and worked solution →The area swept by the hour hand of length 5 cm in 4 hours isRead the answer and worked solution →A chord of a circle of radius 12 cm subtends an angle of 60 degrees at the centre. The area of the corresponding minor segment is approximatelyRead the answer and worked solution →The perimeter of a sector of a circle of radius 14 cm and angle 90 degrees isRead the answer and worked solution →The radius of a wheel is 21 cm. The number of revolutions to cover 924 m isRead the answer and worked solution →A circular flower bed has area 49 pi sq m. Its diameter isRead the answer and worked solution →A circle of radius 21 cm has a sector of angle 120 degrees. The area of the corresponding major segment is approximatelyRead the answer and worked solution →The area swept by the minute hand of length 14 cm in 35 minutes isRead the answer and worked solution →A square is inscribed in a circle of radius r. The area between the circle and the square isRead the answer and worked solution →Two circles of radius 7 cm overlap so that each passes through the other centre. The area of the lens-shaped overlap region (where pi=22/7) is approximatelyRead the answer and worked solution →

Worked practice questions

Area of a circle of radius r is:

  1. π r²
  2. 2 π r
  3. π r
  4. 2 r²
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Correct answer: A. π r²

To find the area of a circle, we use the standard geometric formula that relates the radius of the circle to the space it occupies on a 2D plane. 1. **Identify the Radius**: The radius is given as $r$, which is the distance from the center of the circle to its edge. 2. **Recall the Formula**: The area $A$ of a circle is calculated by taking the square of the radius ($r^2$) and multiplying it by the constant $\pi$ (approximately 3.14159). 3. **Set up the Equation**: $$A = \pi \times r^2$$ 4. **Conclusion**: The correct expression for the area is $\pi r^2$. Note: $2\pi r$ is the formula for the **circumference** (the distance around the circle), not the area.

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Area of a sector subtending angle θ (deg) at the centre of a circle of radius r is:

  1. (θ/180) × π r²
  2. (θ/360) × π r²
  3. π r²
  4. θ × r
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Correct answer: B. (θ/360) × π r²

To find the area of a sector of a circle, we follow these steps: 1. **Total Area**: The total area of a circle with radius $r$ is given by the formula: $$A_{total} = \pi r^2$$ 2. **Total Angle**: A complete circle subtends an angle of $360^\circ$ at its center. 3. **Proportionality**: A sector is a fraction of the entire circle. The ratio of the area of the sector to the total area of the circle is the same as the ratio of the angle subtended by the sector ($\theta$) to the total angle of the circle ($360^\circ$). $$\frac{\text{Area of Sector}}{\text{Total Area}} = \frac{\theta}{360^\circ}$$ 4. **Derivation**: Multiply both sides by the total area: $$\text{Area of Sector} = \frac{\theta}{360^\circ} \times \pi r^2$$ Thus, the area of the sector is $(\theta/360) \times \pi r^2$.

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Volume of a cone with radius r and height h is:

  1. (2/3) π r² h
  2. π r² h
  3. (1/3) π r² h
  4. π r h
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Correct answer: C. (1/3) π r² h

To find the volume of a cone, we compare it to a cylinder with the same radius $r$ and height $h$. 1. **Base Area**: The base of a cone is a circle. The area of this base is given by the formula: $$A = \pi r^2$$ 2. **Relationship to a Cylinder**: A cylinder with the same dimensions has a volume of $V_{cylinder} = \text{Base Area} \times \text{Height} = \pi r^2 h$. 3. **The Cone Factor**: In geometry, it is proven (through calculus or physical displacement experiments) that a cone occupies exactly one-third of the volume of a cylinder with the same base and height. 4. **Final Formula**: Multiplying the cylinder volume by $1/3$, we get: $$V = \frac{1}{3} \pi r^2 h$$ Therefore, the correct option is **(1/3) π r² h**.

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