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A square is inscribed in a circle of radius r. The area between the circle and the square is
A(pi + 2) r squared
B(pi - 2) r squared
C(pi/2 - 2) r squared
D(2 - pi) r squared
Answer & Solution
Correct answer: B. (pi - 2) r squared
1. Square diagonal = 2 r, so side = r (square root of 2); area = 2 r squared.
2. Circle area = pi × r squared.
3. Difference = pi r squared - 2 r squared = (pi - 2) r squared.
_Source: NCERT Class 10 Mathematics, Ch 11 "Areas Related to Circles", §11.2_
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