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The area of a sector subtending 45 degrees at the centre of a circle of radius 8 cm is
A12 pi sq cm
B4 pi sq cm
C8 pi sq cm
D16 pi sq cm
Answer & Solution
Correct answer: C. 8 pi sq cm
1. Area = (45/360) × pi × 8 squared = (1/8) × 64 × pi.
2. = 8 pi sq cm.
3. Hence option A.
_Source: NCERT Class 10 Mathematics, Ch 11 "Areas Related to Circles", §11.2_
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