In triangle PQR, S and T are points on PQ and PR respectively. ST is parallel to QR. If PS = 3, SQ = 6 and PT = 4, then PR equals
- 8
- 10
- 14
- 12
Show answer and solution
Correct answer: D. 12
1. By BPT, PS/SQ = PT/TR. So 3/6 = 4/TR, giving TR = 8.
2. PR = PT + TR = 4 + 8.
3. Hence PR = 12.
_Source: syllabus Mathematics, Ch 6 "Triangles", §6.3_