alleryA circle of radius 21 cm has a sector of angle 120 degrees. The area of the corresponding major segment is approximately
A462 sq cm
B693 sq cm
C231 sq cm
D1192.1 sq cm
Answer & Solution
Correct answer: D. 1192.1 sq cm
1. Major sector area = (240/360) × (22/7) × 21 squared = (2/3) × 1386 = 924 sq cm.
2. Triangle area (isoceles, 120 deg) = (1/2) × 21 × 21 × sin(120) ≈ 190.5; major segment = major sector + triangle.
3. = 924 + ≈ 268.1 ≈ 1192.1 sq cm.
_Source: syllabus Mathematics, Ch 11 "Areas Related to Circles", §11.2_
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