alleryA chord of a circle of radius 12 cm subtends an angle of 60 degrees at the centre. The area of the corresponding minor segment is approximately
A6.5 sq cm
B75.4 sq cm
C32 sq cm
D13.04 sq cm
Answer & Solution
Correct answer: D. 13.04 sq cm
1. Sector area = (60/360) × pi × 12 squared = 24 pi ≈ 75.4 sq cm.
2. Triangle area = (1/2) × 12 × 12 × sin(60) = 36 (square root of 3) ≈ 62.35 sq cm.
3. Segment ≈ 75.4 - 62.35 ≈ 13.04 sq cm.
_Source: syllabus Mathematics, Ch 11 "Areas Related to Circles", §11.2_
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