BITSAT Kinetic Theory of Gases — practice questions
33 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice BITSAT Kinetic Theory of Gases in the app →Ideal gas equation:Postulate of kinetic theory: gas molecules:Pressure exerted by gas (KTG):Avogadro's number:R / N_A =Root-mean-square speed of gas molecules (mass m):Average kinetic energy per molecule (monatomic gas):Degrees of freedom for monatomic gas (e.g., He, Ar):Most probable speed v_mp:Average speed v_avg of molecules:Maxwell speed distribution is:Internal energy of n moles of ideal gas (monatomic):Ratio of specific heats γ for monatomic gas:For ideal gas, C_p - C_v =Two gases of molar masses M₁ and M₂ at same T. Ratio of v_rms:Find v_rms of O₂ at 300 K (M = 32 g/mol, R = 8.314):Graham's law of effusion: rate of effusion ∝For Maxwell-Boltzmann distribution, fraction of molecules with KE > E behaves as:Boyle's law derivation from KTG: at constant T, doubling V causes:For monatomic ideal gas, U/T (heat capacity at const V) per mole:In adiabatic process for ideal gas:For mixture of two ideal gases, total pressure = (Dalton's law):Equipartition: at temperature T, each quadratic DOF carries energy:Mean free path doubles when:At what temperature does v_rms of H₂ equal v_rms of O₂ at 300 K?For diatomic gas at very high T (vibrational modes active), DOF = ?Boltzmann's distribution gives fraction of molecules in energy state E:During adiabatic compression of ideal gas:For an ideal gas in adiabatic process: TV^(γ-1) =Kinetic energy per molecule of monatomic gas at 300 K (k = 1.38 × 10⁻²³):Two containers, equal volume, one with H₂ and one with O₂ at same T, P. Ratio of:For ideal gas, molar heat capacity C_v vs C_p relationship:Speed of sound in ideal gas: