Speed of sound in ideal gas:
AcV
Bsqrt(RT/M)
Cv_sound = sqrt(γRT/M)
Dsqrt(kT)
Answer & Solution
Correct answer: C. v_sound = sqrt(γRT/M)
v_sound = sqrt(γP/ρ) = sqrt(γRT/M). For air (γ=1.4, M=29 g/mol) at 300 K: ≈ 346 m/s. Speed of sound ≈ 70% of v_rms. Sound is a pressure wave whose propagation speed depends on γ.
Related questions
For ideal gas, molar heat capacity C_v vs C_p relationship:Two containers, equal volume, one with H₂ and one with O₂ at same T, P. Ratio of:Kinetic energy per molecule of monatomic gas at 300 K (k = 1.38 × 10⁻²³):For an ideal gas in adiabatic process: TV^(γ-1) =During adiabatic compression of ideal gas:Boltzmann's distribution gives fraction of molecules in energy state E:For diatomic gas at very high T (vibrational modes active), DOF = ?At what temperature does v_rms of H₂ equal v_rms of O₂ at 300 K?