**Gatterman–Koch reaction** formylates benzene using
- $RCOCl$ with $AlCl_3$
- $CHCl_3$ with aq. $NaOH$
- $CO + HCl$ with $AlCl_3$/$CuCl$
- $HCHO$ with conc. $H_2SO_4$
Show answer and solution
Correct answer: C. $CO + HCl$ with $AlCl_3$/$CuCl$
$C_6H_6 + CO + HCl \xrightarrow{AlCl_3, CuCl} C_6H_5CHO$.
Equivalent to a Friedel–Crafts acylation with the in-situ generated formyl cation $HC≡O^+$.