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Effective Atomic Number (EAN) of metal in [Ni(CO)₄]:
A44
B32
C36 (= 28 (Ni) + 4(2) - 0)
D28
Answer & Solution
Correct answer: C. 36 (= 28 (Ni) + 4(2) - 0)
Ni atomic number = 28, oxidation state = 0. CO donates 2 e⁻ each: 4 × 2 = 8. EAN = 28 - 0 + 8 = 36 (Kr-like). 18-electron rule: 8 + 10 = 18 electrons in valence.
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