The correct order of ligand denticity, from smallest to largest, is
AEDTA⁴⁻ < en < H₂O < Cl⁻
BH₂O < NH₃ < en < EDTA⁴⁻
Cen < H₂O < Cl⁻ < EDTA⁴⁻
DCl⁻ < H₂O < en < EDTA⁴⁻
Answer & Solution
Correct answer: D. Cl⁻ < H₂O < en < EDTA⁴⁻
1. Cl⁻ is unidentate (denticity 1).
2. H₂O is also unidentate but is listed alongside Cl⁻ in this ordering.
3. en (ethane-1,2-diamine) is bidentate (denticity 2).
4. EDTA⁴⁻ is hexadentate (denticity 6). So Cl⁻ < H₂O < en < EDTA⁴⁻.
_Source: syllabus Chemistry, Unit 5 "Coordination Compounds", §5.2(c)_
Keep practising Unit 2B1: Transition Metals & Coordination Compounds
Browse all Unit 2B1: Transition Metals & Coordination Compounds questions for JEE Advanced, or explore more Chemistry topics.
Related questions
The correct IUPAC name of [NiCl₂(PPh₃)₂] isThe coordination sphere of K₄[Fe(CN)₆] isChelate complexes tend to be more stable than similar complexes with unidentate ligands. TThe primary and secondary valences of Co in [Co(NH₃)₆]Cl₃ are respectivelyWhich of the following is a homoleptic complex?Which coordination polyhedron does [Ni(CO)₄] adopt?The IUPAC name of [Ni(NH₃)₆]Cl₂ isWhich of these ligands is ambidentate — capable of binding through either of two different