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The correct order of ligand denticity, from smallest to largest, is

AEDTA⁴⁻ < en < H₂O < Cl⁻
BH₂O < NH₃ < en < EDTA⁴⁻
Cen < H₂O < Cl⁻ < EDTA⁴⁻
DCl⁻ < H₂O < en < EDTA⁴⁻
Answer & Solution
Correct answer: D. Cl⁻ < H₂O < en < EDTA⁴⁻
1. Cl⁻ is unidentate (denticity 1). 2. H₂O is also unidentate but is listed alongside Cl⁻ in this ordering. 3. en (ethane-1,2-diamine) is bidentate (denticity 2). 4. EDTA⁴⁻ is hexadentate (denticity 6). So Cl⁻ < H₂O < en < EDTA⁴⁻. _Source: syllabus Chemistry, Unit 5 "Coordination Compounds", §5.2(c)_
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