The correct order of ligand denticity, from smallest to largest, is

Question

Accepted Answer

D. {'text': 'Cl⁻ < H₂O < en < EDTA⁴⁻', 'label': 'D'}

1. Cl⁻ is unidentate (denticity 1).
2. H₂O is also unidentate but is listed alongside Cl⁻ in this ordering.
3. en (ethane-1,2-diamine) is bidentate (denticity 2).
4. EDTA⁴⁻ is hexadentate (denticity 6). So Cl⁻ < H₂O < en < EDTA⁴⁻.
_Source: NCERT Class 12 Chemistry, Unit 5 "Coordination Compounds", §5.2(c)_

Answer

{'text': 'EDTA⁴⁻ < en < H₂O < Cl⁻', 'label': 'A'}

Answer

{'text': 'H₂O < NH₃ < en < EDTA⁴⁻', 'label': 'B'}

Answer

{'text': 'en < H₂O < Cl⁻ < EDTA⁴⁻', 'label': 'C'}