For [Fe(CN)₆]⁴⁻ (low spin), magnetic moment:
A2.83 BM
B5.92 BM
CZERO (low spin d⁶, all paired: t₂g⁶ e_g⁰)
D√(35) BM
Answer & Solution
Correct answer: C. ZERO (low spin d⁶, all paired: t₂g⁶ e_g⁰)
Fe²⁺ is d⁶.
With strong-field ligand CN⁻, low-spin: t₂g⁶ e_g⁰, all 6 electrons paired.
μ = sqrt(n(n+2)) BM = 0. Diamagnetic.
Contrast [Fe(H₂O)₆]²⁺ (weak field): high spin, μ ≈ 4.9 BM.
Keep practising Unit 2B1: Transition Metals & Coordination Compounds
Browse all Unit 2B1: Transition Metals & Coordination Compounds questions for JEE Advanced, or explore more Chemistry topics.
Related questions
The correct IUPAC name of [NiCl₂(PPh₃)₂] isThe coordination sphere of K₄[Fe(CN)₆] isThe correct order of ligand denticity, from smallest to largest, isChelate complexes tend to be more stable than similar complexes with unidentate ligands. TThe primary and secondary valences of Co in [Co(NH₃)₆]Cl₃ are respectivelyWhich of the following is a homoleptic complex?Which coordination polyhedron does [Ni(CO)₄] adopt?The IUPAC name of [Ni(NH₃)₆]Cl₂ is