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HomeJEE MainChemistryCoordination Compounds › For [Fe(CN)₆]⁴⁻ (low spin), magnetic moment:

For [Fe(CN)₆]⁴⁻ (low spin), magnetic moment:

A2.83 BM
B5.92 BM
CZERO (low spin d⁶, all paired: t₂g⁶ e_g⁰)
D√(35) BM
Answer & Solution
Correct answer: C. ZERO (low spin d⁶, all paired: t₂g⁶ e_g⁰)
Fe²⁺ is d⁶. With strong-field ligand CN⁻, low-spin: t₂g⁶ e_g⁰, all 6 electrons paired. μ = sqrt(n(n+2)) BM = 0. Diamagnetic. Contrast [Fe(H₂O)₆]²⁺ (weak field): high spin, μ ≈ 4.9 BM.
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