Relation between equilibrium constant K and E°:
AK = nF
BK = E°
Clog K = nE°/0.0591 (at 25°C)
Dlog K = -nE°
Answer & Solution
Correct answer: C. log K = nE°/0.0591 (at 25°C)
At equilibrium E = 0. From Nernst: 0 = E° - (0.0591/n) log K → log K = nE°/0.0591. Large E° gives large K (strongly spontaneous).
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