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Resistance of a conductivity cell filled with 0.1 M KCl is 100 Ω. Specific conductivity κ of solution (cell constant = 1.5 cm⁻¹):
A100 S/cm
B1.5 × 10⁻² S/cm
C0.0015 S/cm
D0.015 S/cm
Answer & Solution
Correct answer: D. 0.015 S/cm
κ = (1/R) × cell constant = (1/100) × 1.5 = 0.015 S/cm. Cell constant l/A is fixed for the conductivity cell (independent of solution); determined by calibration with standard KCl.
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