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Time to deposit 1.27 g of Cu from CuSO₄ solution at 2 A current (Cu atomic mass = 63.5):
A965 s
B100 s
C1930 s
D19300 s
Answer & Solution
Correct answer: C. 1930 s
Equiv weight = M/n = 63.5/2 = 31.75. Q = (m × n × F)/M = (1.27 × 2 × 96500)/63.5 ≈ 3860 C. t = Q/I = 3860/2 = 1930 s.
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