Time to deposit 1.27 g of Cu from CuSO₄ solution at 2 A current (Cu atomic mass = 63.5):
A965 s
B100 s
C1930 s
D19300 s
Answer & Solution
Correct answer: C. 1930 s
Equiv weight = M/n = 63.5/2 = 31.75. Q = (m × n × F)/M = (1.27 × 2 × 96500)/63.5 ≈ 3860 C. t = Q/I = 3860/2 = 1930 s.
Related questions
For an electrochemical cell operating spontaneously, ΔG° is related to E°_cell byWhich of the following statements about electrode potentials is INCORRECT?The overall cell reaction of the lead storage battery on discharge isThe primary cell that cannot be reused after its EMF drops to zero is exemplified byRusting of iron requires which two chemicals in contact with the metal?Fuel cells directly convertThe specific conductivity of a 0.1 M KCl solution is 1.29 × 10⁻² S/cm. The molar conductivMolar conductivity of a strong electrolyte at concentration c is related to its limiting v