Lead acid battery (used in cars) overall reaction:
ALi + H
BPbCl₂
CPb + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O (during discharge)
DPb + O₂
Answer & Solution
Correct answer: C. Pb + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O (during discharge)
Anode (discharge): Pb + SO₄²⁻ → PbSO₄ + 2e⁻. Cathode: PbO₂ + 4H⁺ + SO₄²⁻ + 2e⁻ → PbSO₄ + 2H₂O. Net: Pb + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O. Rechargeable. EMF ≈ 2.05 V per cell, hence 12 V in 6-cell.
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