Faraday constant F is:
A6 × 10²³
B96500 C/mol (charge of 1 mole of electrons)
C10⁻¹⁹ C
D10000 C
Answer & Solution
Correct answer: B. 96500 C/mol (charge of 1 mole of electrons)
F = N_A × e ≈ 6.022 × 10²³ × 1.602 × 10⁻¹⁹ ≈ 96485 C/mol. Charge carried by 1 mole of electrons.
Related questions
The electrolytes of the two half-cells are joined by a:The two portions of a galvanic cell are also called:In the Daniell cell, zinc dissolves at the anode and copper:A negative standard potential marks a reducing agent that is:Going from top to bottom of the table, the electrode potential:The weakest oxidising agent in the table of potentials is:The most powerful reducing agent in aqueous solution is:The weakest reducing agent in the table of potentials is: