For Daniell cell, cell reaction Zn + Cu²⁺ → Zn²⁺ + Cu. Cell EMF:
AE°_Cu + E°_Zn
B0 V
C-1.10 V
DE°_Cu - E°_Zn = 0.34 - (-0.76) = 1.10 V
Answer & Solution
Correct answer: D. E°_Cu - E°_Zn = 0.34 - (-0.76) = 1.10 V
E°_cell = E°_cathode - E°_anode (both as reduction potentials). For Daniell: E°_cell = E°(Cu²⁺/Cu) - E°(Zn²⁺/Zn) = 0.34 - (-0.76) = 1.10 V. Positive E°, so reaction is spontaneous.
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