Home › JEE Advanced › Chemistry › Electrochemical Series › In electrolysis of CuSO4 with Pt electrodes, the…
In electrolysis of CuSO4 with Pt electrodes, the cathode product is:
ASO2
BO2 gas
CCu metal (Cu²⁺ + 2e⁻ → Cu)
DH2 gas
Answer & Solution
Correct answer: C. Cu metal (Cu²⁺ + 2e⁻ → Cu)
At cathode, reduction occurs. Cu²⁺ is more easily reduced than H+ (in dilute solution). So Cu²⁺ + 2e⁻ → Cu(s). At anode, water/SO4²⁻ gets oxidized; O2 evolves.
Related questions
The electrolytes of the two half-cells are joined by a:The two portions of a galvanic cell are also called:In the Daniell cell, zinc dissolves at the anode and copper:A negative standard potential marks a reducing agent that is:Going from top to bottom of the table, the electrode potential:The weakest oxidising agent in the table of potentials is:The most powerful reducing agent in aqueous solution is:The weakest reducing agent in the table of potentials is: