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A 0.1 M weak acid HA has Λ_m = 10 S·cm²/mol; at infinite dilution Λ_m^0 = 400. Degree of dissociation α:
A0.25
B0.0025
C2.5
D0.025
Answer & Solution
Correct answer: D. 0.025
α = Λ_m / Λ_m^0 = 10/400 = 0.025 (i.e. 2.5% dissociation). For weak electrolytes, dissociation increases as concentration decreases (or dilution increases).
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