At 25°C, ratio of Nernst factor 0.0591/n to RT/(nF) ln 10 in SI units:
A0.434
B2.303
CEqual magnitude (both representations)
DAbout 1
Answer & Solution
Correct answer: C. Equal magnitude (both representations)
0.0591 = (RT/F)(ln 10) at 25°C. So (0.0591/n) log Q (with log base 10) is equivalent to (RT/(nF)) ln Q (with natural log). They are the same formula in different bases.
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