For Cu²⁺ + 2e⁻ → Cu, how much charge to deposit 0.5 mol Cu? (F = 96500 C/mol)
A48,250 × 2 C
B193,000 C
C48,250 C
D96,500 C
Answer & Solution
Correct answer: D. 96,500 C
For 0.5 mol Cu, need 0.5 × 2 = 1 mol electrons = 1 × 96500 = 96,500 C. (m = Q M / (nF), solving for Q.)
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