A is twice as fast as B. Working together they finish a job in 8 days. A alone would take:
A10 days
B16 days
C24 days
D12 days
Answer & Solution
Correct answer: D. 12 days
1. If B does one unit a day, A does two units a day.
2. Together they do 3 units a day.
3. In 8 days they finish the job, so the whole job is 3 x 8 = 24 units.
4. A alone does 2 units a day, so A needs 24 / 2 = 12 days.
5. As a check, B alone would need 24 days, which is twice A's time, exactly as stated.
_Source: syllabus Maths, Ch 11 'Direct and Inverse Proportions', S11.3 Inverse Proportion_
Keep practising Time and Work
Browse all Time and Work questions for AFCAT, or explore more Quantitative Aptitude topics.
Related questions
For a fixed amount of work, the product of the number of workers and the days taken is:A can finish a job in 20 days. After working 5 days he leaves. The fraction of work left iA pipe fills a tank in 6 hours while an outlet empties it in 8 hours. With both open the tA and B together finish a job in 12 days. A alone takes 20 days. B alone would take:A can do a piece of work in 10 days and B in 15 days. Working together they finish it in:If 12 workers can complete a task in 8 days, 16 workers will complete it in:If 6 men finish a job in 10 days, how many days will 4 men take at the same rate?As the number of workers on a job increases, the time taken to finish it: