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The oxidation state of Fe in K₄[Fe(CN)₆] is

A+1
B+4
C+3
D+2
Answer & Solution
Correct answer: D. +2
1. Overall charge of K₄[Fe(CN)₆] is zero. 2. 4 K⁺ contribute +4 total. 3. 6 CN⁻ contribute −6 total. 4. So Fe must be +2 to balance: 4 + Fe − 6 = 0 → Fe = +2. _Source: syllabus Chemistry, Unit 5 "Coordination Compounds", §5.2(g)_
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