The oxidation state of Fe in K₄[Fe(CN)₆] is
A{'text': '+1', 'label': 'A'}
B{'text': '+4', 'label': 'B'}
C{'text': '+3', 'label': 'C'}
D{'text': '+2', 'label': 'D'}
Answer & Solution
Correct answer: D. {'text': '+2', 'label': 'D'}
1. Overall charge of K₄[Fe(CN)₆] is zero.
2. 4 K⁺ contribute +4 total.
3. 6 CN⁻ contribute −6 total.
4. So Fe must be +2 to balance: 4 + Fe − 6 = 0 → Fe = +2.
_Source: NCERT Class 12 Chemistry, Unit 5 "Coordination Compounds", §5.2(g)_
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