Using Euclid's division algorithm, what is the HCF of 135 and 225?
A15
B25
C35
D45
Answer & Solution
Correct answer: D. 45
**Apply the algorithm:** $225=135\times 1+90$, then $135=90\times 1+45$, and $90=45\times 2+0$.
When the remainder becomes 0, the last divisor is the HCF.
**Hence the HCF is 45.**
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