If $\alpha,\beta,\gamma$ are the zeroes of the cubic polynomial $ax^3+bx^2+cx+d$, then $\alpha\beta\gamma$ is equal to

For a cubic polynomial $ax^3+bx^2+cx+d$, the relations are $\alpha+\beta+\gamma=-\dfrac{b}{a}$, $\alpha\beta+\beta\gamma+\gamma\alpha=\dfrac{c}{a}$, and $\alpha\beta\gamma=-\dfrac{d}{a}$.