alleryIf $\alpha,\beta,\gamma$ are the zeroes of the cubic polynomial $ax^3+bx^2+cx+d$, then $\alpha\beta\gamma$ is equal to
A$\dfrac{d}{a}$
B$-\dfrac{b}{a}$
C$\dfrac{c}{a}$
D$-\dfrac{d}{a}$
Answer & Solution
Correct answer: D. $-\dfrac{d}{a}$
For a cubic polynomial $ax^3+bx^2+cx+d$, the relations are $\alpha+\beta+\gamma=-\dfrac{b}{a}$, $\alpha\beta+\beta\gamma+\gamma\alpha=\dfrac{c}{a}$, and $\alpha\beta\gamma=-\dfrac{d}{a}$.
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