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For the polynomial $p(x)=x^2-3x-4$, what is the value of $p(-1)$?
A$-8$
B$-2$
C$0$
D$2$
Answer & Solution
Correct answer: C. $0$
Substitute $x=-1$ into $p(x)$: $(-1)^2-3(-1)-4=1+3-4=0$. Therefore, $p(-1)=0$.
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