alleryIf $\alpha$ and $\beta$ are the zeroes of the quadratic polynomial $ax^2+bx+c$ with $a\neq 0$, then $\alpha+\beta$ equals
A$\dfrac{c}{a}$
B$\dfrac{b}{a}$
C$-\dfrac{b}{a}$
D$-\dfrac{c}{a}$
Answer & Solution
Correct answer: C. $-\dfrac{b}{a}$
For a quadratic polynomial $ax^2+bx+c$, the relation between zeroes and coefficients is $\alpha+\beta=-\dfrac{b}{a}$ and $\alpha\beta=\dfrac{c}{a}$.
**So the required value is $-\dfrac{b}{a}$.**
Keep practising Number Systems
Browse all Number Systems questions for Andhra Pradesh SSC (Class 10), or explore more Mathematics topics.
Related questions
Which of the following is not a polynomial in the variable $x$?The zero of the linear polynomial $ax+b$ with $a\neq 0$ isFor the polynomial $p(x)=x^2-3x-4$, what is the value of $p(-1)$?Which statement is true for a polynomial of degree $n$?The zeroes of the quadratic polynomial $x^2+7x+10$ areA quadratic polynomial has sum of zeroes $-3$ and product of zeroes $2$. Which of the follIf $\alpha,\beta,\gamma$ are the zeroes of the cubic polynomial $ax^3+bx^2+cx+d$, then $\aIf $6=2\times 3$ and $20=2^2\times 5$, then their HCF and LCM respectively are