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The zeroes of the quadratic polynomial $x^2+7x+10$ are
A$2$ and $5$
B$-2$ and $-5$
C$-2$ and $5$
D$2$ and $-5$
Answer & Solution
Correct answer: B. $-2$ and $-5$
Factorise: $x^2+7x+10=(x+2)(x+5)$. The polynomial is zero when $x+2=0$ or $x+5=0$, so the zeroes are $-2$ and $-5$.
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