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The spin-only magnetic moment μ (in Bohr Magnetons, BM) for n unpaired electrons is given by:
An × 1.73 BM
Bn² BM
C√n BM
D√(n(n+2)) BM
Answer & Solution
Correct answer: D. √(n(n+2)) BM
**Spin-only formula: μ = √(n(n+2)) BM** (in units of Bohr Magnetons). E.g., 1 unpaired → √3 = 1.73 BM; 4 → √24 = 4.90 BM; 5 → √35 = 5.92 BM. Used to identify n_unpaired from experimental μ.
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