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In [Co(NH₃)₆]³⁺, the hybridisation of Co and the resulting magnetic behaviour are:
Asp³d² (outer orbital), paramagnetic
Bsp³, tetrahedral, paramagnetic
Cd²sp³ (inner orbital), diamagnetic — strong-field NH₃ pairs all 3d electrons of Co³⁺(d⁶)
Ddsp², square planar, diamagnetic
Answer & Solution
Correct answer: C. d²sp³ (inner orbital), diamagnetic — strong-field NH₃ pairs all 3d electrons of Co³⁺(d⁶)
Co³⁺ = d⁶. NH₃ is a (borderline) strong-field ligand here → pairs all 6 electrons into the lower three 3d orbitals → 2 vacant 3d orbitals available → **d²sp³ inner-orbital (low-spin) octahedral**. No unpaired electrons → **diamagnetic**.
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