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In K₃[Fe(C₂O₄)₃], the oxidation state of Fe is:

A+2
B+6
C+3
D+1
Answer & Solution
Correct answer: C. +3
**Charge balance:** 3(+1) [K] + x [Fe] + 3(−2) [oxalate, each is −2] = 0 → 3 + x − 6 = 0 → **x = +3**. **So Fe(III) in K₃[Fe(C₂O₄)₃].**
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