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A car turns a corner of radius 50 m at 20 m/s. Minimum coefficient of friction needed (g = 10):
A0.2
B0.4
C0.6
D0.8
Answer & Solution
Correct answer: D. 0.8
Centripetal force = m v²/r. Friction must supply this: μmg ≥ mv²/r → μ ≥ v²/(rg) = 400/500 = 0.8. So minimum μ = 0.8.
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