Start learning →

NEET UG Unit 1C: Kinematics: Relative & Circular Motion — practice questions

Explore 33 free Unit 1C: Kinematics: Relative & Circular Motion questions in NEET UG Physics. Open each question or exercise to read its content, reference answers and available explanation.

Practise Unit 1C: Kinematics: Relative & Circular Motion with Quill →

Unit 1C: Kinematics: Relative & Circular Motion questions and exercises with answers

Showing questions 1–30 of 33.

A constant force does work W on a body that starts from rest. If the same force acts for twice the displacement, the kinetic energy becomes:Read the answer and worked solution →For a particle moving along a straight line under a varying force F(x), the work done from x = a to x = b is:Read the answer and worked solution →A heavy body and a light body have the same kinetic energy. The body with the greater momentum is:Read the answer and worked solution →The average power for a process is computed as:Read the answer and worked solution →The dimensional formula of power is:Read the answer and worked solution →The SI unit of the universal gravitational constant G is:Read the answer and worked solution →The approximate value of G is:Read the answer and worked solution →The acceleration due to gravity g at the Earth's surface (radius R, mass M_E) is:Read the answer and worked solution →Variation of g with height h above the Earth's surface (for h ≪ R) is approximately:Read the answer and worked solution →At a depth d below the Earth's surface (assuming uniform density), g varies as:Read the answer and worked solution →The value of g at the centre of a uniform spherical Earth is:Read the answer and worked solution →Kepler's first law (orbits) states that planetary orbits are:Read the answer and worked solution →Kepler's second law states that the line joining a planet to the Sun sweeps out:Read the answer and worked solution →Kepler's third law gives the relation T² ∝ ___, where T is the orbital period and a the semi-major axis:Read the answer and worked solution →The gravitational potential energy of a two-particle system separated by r (taking U → 0 as r → ∞) is:Read the answer and worked solution →The orbital speed of a satellite in a circular orbit of radius r around a planet of mass M is:Read the answer and worked solution →The escape speed from the surface of a planet of mass M and radius R is:Read the answer and worked solution →The escape speed at the Earth's surface is approximately:Read the answer and worked solution →The orbital speed of a satellite in a low Earth orbit (just above the surface) is approximately:Read the answer and worked solution →For a satellite, escape speed v_e and orbital speed v_o (at the same height) are related by:Read the answer and worked solution →A geostationary satellite orbits the Earth with a period of approximately:Read the answer and worked solution →A geostationary satellite stays above the:Read the answer and worked solution →For a satellite in a circular orbit, total mechanical energy E and kinetic energy K are related by:Read the answer and worked solution →The gravitational field inside a uniform spherical shell of mass is:Read the answer and worked solution →For points outside a spherically symmetric body, gravitational attraction is as if all mass were concentrated at the:Read the answer and worked solution →The gravitational potential V at a point at distance r from a point mass M is:Read the answer and worked solution →At a great distance from the Earth, the gravitational potential approaches:Read the answer and worked solution →The path of a projectile launched from Earth with a speed equal to escape velocity (radially, ignoring air drag) is:Read the answer and worked solution →If the radius of a planet doubles while its mass stays the same, g at its surface becomes:Read the answer and worked solution →Two satellites orbit a planet at radii r and 4r in circular orbits. The ratio of their periods T1 : T2 is:Read the answer and worked solution →

Worked practice questions

A constant force does work W on a body that starts from rest. If the same force acts for twice the displacement, the kinetic energy becomes:

  1. 2W
  2. W
  3. W/2
  4. 4W
Show answer and solution

Correct answer: A. 2W

W = F·s; doubling s with same F doubles work and hence KE (starting from rest).

Open this question →

For a particle moving along a straight line under a varying force F(x), the work done from x = a to x = b is:

  1. F(b)−F(a)
  2. F(a)·(b−a)
  3. F(b)·(b−a)
  4. ∫_a^b F(x) dx
Show answer and solution

Correct answer: D. ∫_a^b F(x) dx

Work = area under F–x curve.

Open this question →

A heavy body and a light body have the same kinetic energy. The body with the greater momentum is:

  1. the lighter one
  2. the heavier one
  3. both have equal momentum
  4. cannot be determined
Show answer and solution

Correct answer: B. the heavier one

p = √(2mK); for fixed K, p ∝ √m, so heavier ⇒ larger momentum.

Open this question →

How to practise

  1. Choose a Unit 1C: Kinematics: Relative & Circular Motion question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

Put it into practice

Continue with Unit 1C: Kinematics: Relative & Circular Motion practice for NEET UG. Read explanations as you go. No signup form needed to start.

Practise Unit 1C: Kinematics: Relative & Circular Motion →

More Physics topics

Electric Charges and FieldsMoving Charges and MagnetismRay Optics and Optical InstrumentsSemiconductor ElectronicsCurrent ElectricityDual Nature of Radiation and MatterKinetic Theory & OscillationsSystem of Particles and Rotational Motion