31% ethylene glycol (62 g/mol) by mass in water: mole fraction of glycol?
- 0.130
- 0.115
- 0.885
- 0.310
Show answer and solution
Correct answer: B. 0.115
In 100 g there are 31/62 = 0.5 mol glycol and 69/18 = 3.83 mol water, so x = 0.5/4.33 = 0.115.
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Correct answer: B. 0.115
Correct answer: B. Moles of solute per litre of solution
Correct answer: A. Molarity (M)
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