31% ethylene glycol (62 g/mol) by mass in water: mole fraction of glycol?
A0.130
B0.115
C0.885
D0.310
Answer & Solution
Correct answer: B. 0.115
In 100 g there are 31/62 = 0.5 mol glycol and 69/18 = 3.83 mol water, so x = 0.5/4.33 = 0.115.
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