Inverse of [[2,0],[0,3]]:
- [[1/2,0],[0,1/3]]
- [[2,0],[0,3]]
- [[3,0],[0,2]]
- [[1,0],[0,1]]
Show answer and solution
Correct answer: A. [[1/2,0],[0,1/3]]
For diagonal matrix [[a,0],[0,b]], inverse is [[1/a, 0],[0, 1/b]].
**So [[2,0],[0,3]]⁻¹ = [[1/2,0],[0,1/3]].**