Inverse of [[2,0],[0,3]]:
A[[1/2,0],[0,1/3]]
B[[2,0],[0,3]]
C[[3,0],[0,2]]
D[[1,0],[0,1]]
Answer & Solution
Correct answer: A. [[1/2,0],[0,1/3]]
For diagonal matrix [[a,0],[0,b]], inverse is [[1/a, 0],[0, 1/b]]. So [[2,0],[0,3]]⁻¹ = [[1/2,0],[0,1/3]].
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