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Karnataka PUC I Gravitation — practice questions — page 3

Explore 89 free Gravitation questions in Karnataka PUC I Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Gravitation questions and exercises with answers

Showing questions 61–89 of 89.

The acceleration due to gravity g at height h above Earth's surface (radius R) is approximatelyRead the answer and worked solution →Kepler's third law of planetary motion states that the square of the orbital period T is proportional toRead the answer and worked solution →The value of g on the Moon's surface compared with Earth's g is aboutRead the answer and worked solution →The escape velocity from Earth's surface is approximatelyRead the answer and worked solution →An orbiting satellite has an orbital speed v = √(G M / r). If the orbital radius r is quadrupled, the new speed isRead the answer and worked solution →The gravitational potential energy of two point masses m₁ and m₂ separated by distance r is (taking U = 0 at infinity)Read the answer and worked solution →A geostationary satellite orbits Earth at a height where its period equalsRead the answer and worked solution →The variation of g with depth d below Earth's surface (assuming uniform density) isRead the answer and worked solution →For a body in a circular orbit around Earth of radius r, the ratio of kinetic energy to total mechanical energy isRead the answer and worked solution →Conserved, or not conserved?Read the answer and worked solution →True or false: conservation under gravityRead the answer and worked solution →Complete the weightlessness explanationRead the answer and worked solution →True or false: weightlessnessRead the answer and worked solution →Kepler's third lawRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Tap every quantity conserved for orbital motionRead the answer and worked solution →Flip and pair: law with what it saysRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Order the reasoning: why an astronaut floatsRead the answer and worked solution →True or false: Kepler's lawsRead the answer and worked solution →Which law is being described?Read the answer and worked solution →Orbits and satellitesRead the answer and worked solution →Tap every true statement about orbital motionRead the answer and worked solution →Complete Kepler's third lawRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Flip and pair: statement with its subjectRead the answer and worked solution →Assertion and reason: orbitsRead the answer and worked solution →

Worked practice questions

The acceleration due to gravity g at height h above Earth's surface (radius R) is approximately

  1. g × (R + h)
  2. g × (1 + 2h/R)
  3. g × (1 − 2h/R)
  4. g × (R − h)
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Correct answer: C. g × (1 − 2h/R)

1. g_h = g × R² / (R + h)². 2. For h ≪ R, expand: (1 + h/R)⁻² ≈ 1 − 2h/R. 3. So g_h ≈ g × (1 − 2h/R) to first order. 4. This is the fractional decrease in g as we rise above Earth's surface. _Source: syllabus Physics, Ch 7 "Gravitation", §7.4_

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Kepler's third law of planetary motion states that the square of the orbital period T is proportional to

  1. The radius of the orbit r
  2. 1 / a²
  3. 1 / r
  4. The cube of the semi-major axis a³
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Correct answer: D. The cube of the semi-major axis a³

1. Kepler analysed Tycho Brahe's planetary data. 2. His third law: T² ∝ a³, where a is the semi-major axis of the elliptical orbit. 3. Equivalently: T² / a³ = 4 π² / (G M) is the same for all planets around the Sun. 4. For circular orbits, a is simply the orbital radius. _Source: syllabus Physics, Ch 7 "Gravitation", §7.5_

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The value of g on the Moon's surface compared with Earth's g is about

  1. 1/6 of Earth's g
  2. Same
  3. Twice Earth's g
  4. 10 times Earth's g
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Correct answer: A. 1/6 of Earth's g

1. g = G M / R² depends on mass M and radius R of the body. 2. Moon has M much less and slightly smaller R than Earth. 3. Numerically, g_moon ≈ 1.62 m/s² ≈ (1/6) × 9.8 m/s². 4. So astronauts weigh about 1/6 of their Earth weight on the Moon. _Source: syllabus Physics, Ch 7 "Gravitation", §7.4_

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More Physics topics

Laws of MotionWork, Energy and PowerKinetic Theory & OscillationsMechanical Properties of Solids and FluidsMotion in a PlaneSystem of Particles and Rotational MotionThermal Properties of Matter & ThermodynamicsUnits, Measurements and Motion in a Straight Line