The value of g on the Moon's surface compared with Earth's g is about
A{'text': "1/6 of Earth's g", 'label': 'A'}
B{'text': 'Same', 'label': 'B'}
C{'text': "Twice Earth's g", 'label': 'C'}
D{'text': "10 times Earth's g", 'label': 'D'}
Answer & Solution
Correct answer: A. {'text': "1/6 of Earth's g", 'label': 'A'}
1. g = G M / R² depends on mass M and radius R of the body.
2. Moon has M much less and slightly smaller R than Earth.
3. Numerically, g_moon ≈ 1.62 m/s² ≈ (1/6) × 9.8 m/s².
4. So astronauts weigh about 1/6 of their Earth weight on the Moon.
_Source: NCERT Class 11 Physics, Ch 7 "Gravitation", §7.4_
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