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The value of g on the Moon's surface compared with Earth's g is about

A1/6 of Earth's g
BSame
CTwice Earth's g
D10 times Earth's g
Answer & Solution
Correct answer: A. 1/6 of Earth's g
1. g = G M / R² depends on mass M and radius R of the body. 2. Moon has M much less and slightly smaller R than Earth. 3. Numerically, g_moon ≈ 1.62 m/s² ≈ (1/6) × 9.8 m/s². 4. So astronauts weigh about 1/6 of their Earth weight on the Moon. _Source: syllabus Physics, Ch 7 "Gravitation", §7.4_
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